Jason demonstrates how to estimate the effective wattage of his home made solar water heater. Also, Jason’s water heating element is shaped in such a way that it more coincides with a plane of focal points, characteristic of a semi-circular vs. a parabolic reflector. Jason’s 5 ft long device gave an estimated maximum output of between 200 – 400W.
Hello! Thanks a lot for this helpful video. By the way, I notice many people keep on talking about Xobotano Home Energy (do a search on google), but I’m not sure if it’s good. Have you tried this alternative home energy known as Xobotano Home Energy? I have heard many unbelivable things about it.
Hana Bindrim
October 24, 2012 at 4:00 pm
It still surprises me, how lots of people have no idea about Xobotano Home Energy (do a google search), although many people save a large amount of money because of this alternative energy. Thanks to my mate who told me about Xobotano Home Energy, I’ve slashes my electric bill by 75% in less than 30 days
JamesLewis16037a
October 24, 2012 at 4:51 pm
Nice presentation. What do you use inside the pipe in case we get bellow Zero Degree?
ipopa2000
October 24, 2012 at 5:20 pm
Did you use high temp heat paint on your pipe , as i did not see you paint your pipe, in your video, if you did not, your not getting, all the heat you can from that unit. Good looking set up .
David Roberts
October 24, 2012 at 6:09 pm
interesting to double up the inner pipe however do you not lose your ‘thermoshiphon effect’? also i think you’d be better off having the trough standing (as opposed to horizontal) ideally at around 45º. also another concern is freezing temperatures in winter, particularly in the uk where i live. i’m afraid the pipe may freeze up and burst despite being encased behind an acrylic sheet. in any case very good vid, i too follow dan rojas, he is mad!
caitoxose
October 24, 2012 at 6:53 pm
A nice project and very well presented, Thank you for sharing. 🙂
barumman
October 24, 2012 at 7:40 pm
Problem…..the pump is in the water dissipating heat. You can not pump water with electricity and not generate heat. You can retest two 24 hour tests. One with the collector in the sun and one with the collector in the koi pond. The small pump can easily heat 6 gallons of water.
leaktech1
October 24, 2012 at 8:35 pm
It’d be more efficient if the water went the same direction down both pipes. Currently, you have the coldest and hottest section of pipe touching each other. It’s basically a heat exchanger.
blurglide
October 24, 2012 at 9:10 pm
You sound like a young Richard Dawkins. 🙂 Nice video.
amazonhippie
October 24, 2012 at 10:01 pm
Do you need the pump? As the water heats and expands it should push itself out into the bucket and suck more cold water through…
noreplyism
October 24, 2012 at 10:18 pm
Dan sells those on his website.
seven7arrows
October 24, 2012 at 10:44 pm
it’s nice to see when people back their experiments with some simple physics. not many people even record data and/or share it!
shutinanxiety
October 24, 2012 at 11:09 pm
you need to make a glass square tube case over your pipe, get some glass cut
ie 2 inch wide by the desired length, make a jig ie v shap trough and silicone the glass 90 to eachother use hight temp silicon leave to dry, make other sides the same silicone all sides, get 1/4 thick brass plate drill hole need as need for you pipe, buy some threadable air nib ie just like tire steam, then silicon end plates
leave to dry with pipe installed paint flate black, then vacum air out of tube…
eloid777
October 24, 2012 at 11:42 pm
dude, you should fit this parabolic collector according to the optimum angel or try to put sun tracker to improve the efficiency (W/sq)
I’m also doing some experiments like this and i get 800W/sq
Hanibaleken
October 25, 2012 at 12:31 am
I really liked it, what are you doing with it now? Are you heating water for washing or some specific purpose?
preparedchipmunk
October 25, 2012 at 1:01 am
Wish we could get our hands on those evacuated or vacuum tubes for this type of heater like on one of Dan’s vids.
Your effective surface area seems to be: 5feet x 6in? or = 5 ft x 0.5 which is 2.5 sq feet = 0.232 sq meters. In good sunlight and if your system axis is perpendicular to the sun, then 1000W per sq. meter is expected. At about 23 percent of that area then, you could expect then about 232 W max it seems. Am I close, or does anyone else have any input on these numbers?
trailkeeper
October 25, 2012 at 1:42 am
Quite impressive.
cronusone
October 25, 2012 at 2:36 am
Well done - great idea!
Bethhable
October 25, 2012 at 3:01 am