Bea raised a total of 28 cows and turkeys. There were 96 legs in all. How many cows&how many tukeys are there?
Question by Dianna S: Bea raised a total of 28 cows and turkeys. There were 96 legs in all. How many cows&how many tukeys are there?
I need this right away please.please thank you to who ever gets this!!!
Feel free to answer in the comment section below
4 Responses to Bea raised a total of 28 cows and turkeys. There were 96 legs in all. How many cows&how many tukeys are there?
Leave a Reply
20 cows & 8 turkeys
mail2me_1
July 28, 2012 at 2:49 am
x = number of cows
y= number of turkeys
4x + 2y= 96
x + y = 28
4x + 2y = 96
-2x+ -2y= -56
subtract
2x = 40
x= 20
x+ y = 28
20 + y = 28
y = 8
check with
4x + 2y = 96
4(20) + 2y = 96
80+ 2y = 96
2y = 16
y = 8
IAskUAnswer
July 28, 2012 at 3:03 am
This is a system with 2 variables and 2 equations. Let T represent the number of turkeys, and C the number of cows. Now we can write this sentence mathematically! We know that:
(1) T+C= 28
and
(2) 2T + 4C = 96 (b/c turkeys have 2 legs and cows have 4)
Now you just have to substitute and solve! You could re-arrange equation one into T=28-C. Putting that into equation 2 gives you:
2(28-C) + 4C = 96
Simplify : 2C=40
So there are 20 cows and 8 turkeys!
imacampie
July 28, 2012 at 3:54 am
c+t=28
4c+2t=96
t=28-c
4c+2(28-c)=96
4c+56-2c=96
2c+56-56=96-56
2c=40
c=20
t=8
Dave aka Spider Monkey
July 28, 2012 at 4:20 am